Fun Stuff > CHATTER
Can't Think of a Breaking Bad Pun For the Title: Let's Do Some Math!
Jace:
--- Quote from: Carl-E on 21 Oct 2013, 07:31 ---But you do have r. The circle's area is 9 mi2, so the radius is sqrt(9/pi).
I know, the 9th hour is not a pretty one...
--- End quote ---
Ah, of course. Although I think solving for r put it in a more manageable form when doing the derivative and then plugging in numbers.
Carl-E:
--- Quote from: de_la_Nae on 21 Oct 2013, 08:43 ---hate/love :psyduck:
--- End quote ---
Glad you have your priorities straight! :-D
Loki:
I wish to use this opportunity to declare my hatred towards absolute-value inequalities.
Which also contain fractions in the abs(). Ohgod why :psyduck:
Edit: okay, so I had one of those inequalities resolve into (5>0) and (x>5/4). Why does the fact that I got a statement which is always true not mean that x can be an arbitrary number?
snalin:
If the inequalities resolve into two inequalities, then both has to be followed. If one does not have x in it, then you can disregard it, and x>5/4 is the only restriction.
Try to plug in 5/4, values under 5/4, and values over 5/4 into the original inequality. If your solution is correct, only the group over 5/4 should give correct statements.
ankhtahr:
Damn. I definitely need to learn how to prove stuff. They assume that we learned it in school, but I didn't.
Also, how can I show that ? I can see that it has a global maximum at 1 and -1, but I just don't know how to show that.
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