@katsmeat

Yep, that was a Me 109.

Bf 109, please. A G model from the looks of it, G-10 perhaps?

As for dropped rocks/tungsten rods - it takes energy to de-orbit. If you're in a Molniya orbit, only a bit to make the eccentricity a little higher so the perigee intersects the Earth's surface, but you can't get more energy out than you put in. If you're in a circular orbit, "dropping" means it just stays where it is, in orbit. Accelerate, it goes higher, decelerate, it goes lower.

Molniya orbit

If at apogee (the high part) just a tiny deceleration is enough to increase eccentricity so you get lithobraking. However you enter the atmosphere at a shallow angle, and may burn up or even skip, depending on aerodynamics.

Anyway, as has been pointed out, you can't get a 10 megaton bang out without expending a >10 megaton amount of energy to put it up there. Not quite true, you can play games with orbits, sucking energy off the Earth or Lunar rotation, slowing them down by a smidgen, and increasing your energy a lot... but that takes fancy footwork, probably going to Venus and back a few times, and many years. The kind of thing you only do on long range interplanetary missions.

When it comes to space weaponry, the go-to site is Project Rho's Atomic Rockets.

*Rick Robinson's First Law of Space Combat*

An object impacting at 3 km/sec delivers kinetic energy equal to its mass in TNT.3km/sec is the velocity of an object falling for 300 secs in a constant 1g field in a vacuum (just about). 90000 metres, just on the edge of space. But to double the velocity - so get a yield of 4kg of TNT per kg of mass - you'd need 600 secs of falling - 360,000 metres. Low Earth Orbit. And so on.

Taking things to extremes, 454 kt is the yield of 1 gram at 99.9% c. So a 1kg mass at 99.9C gives 454 Mt.

Sources:

http://www.projectrho.com/public_html/rocket/spacegunconvent.phphttp://www.projectrho.com/public_html/rocket/spacegunexotic.php